for self practice
Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
Example 1:

Input: root = [1,2,3,null,5,null,4] Output: [1,3,4]
Example 2:
Input: root = [1,null,3] Output: [1,3]
Example 3:
Input: root = [] Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 100]. -100 <= Node.val <= 100
package practice;
import java.util.*;
public class BinaryTreeRightSideView {
//https://leetcode.com/problems/binary-tree-right-side-view/solution/
public List<Integer> rightSideView(TreeNode root) {
if (root == null) return new ArrayList<Integer>();
List<Integer> list=new ArrayList<>();
Queue<TreeNode> queue=new LinkedList<>();
queue.offer(root);
while(!queue.isEmpty()){
int levelsize=queue.size();
for(int i=0; i<levelsize; i++){
TreeNode node=queue.poll();
if(i==(levelsize-1)){
list.add(node.val);
}
if(node.left!=null){
queue.offer(node.left);
}
if(node.right!=null){
queue.offer(node.right);
}
}
}
return list;
}
}
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